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Consider L = { abwba : w in Sigma but does not contain the substring ba } over Sigma = { a ,

Consider L ={abwba : w in \Sigma
but does not contain the substring ba} over \Sigma ={a, b, c, d}.
1. Show that L is a regular language by drawing a DFA for it, with the DFA having
as few states as you can.
2. Draw an NFA for L with as few states as you can.
3. Convert the NFA to a GNFA.
4. Convert the GNFA to an RE (Regular Expression) using the procedure discussed
in class. Show the steps. You may, but are not required to, shorten intermediate
REs using identities like R= and \epsi R = R and R \cup = R to reduce expression
swell
can it please be done with a pen

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