() Consider the definite integral: 2/6 x3 dx. 1/6 6x2 - 1 The most appropriate substitution to simplify this integral is x = g(t), where g(t) = t^3/sqrt(6t^2-1) After making this substitution and simplifying (using trig identities), we obtain the integral f(t) = a= and b = After evaluating this integral we obtain: 2/6 x3 dx = 1/6 6x2 - 1 f(t) dt, where a