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Consider the following address: 189.166.18.0/24. Give the: subnet mask, network, and broadcast addresses, for the first subnet upon borrowing 2 bit from the host
Consider the following address: 189.166.18.0/24. Give the: subnet mask, network, and broadcast addresses, for the first subnet upon borrowing 2 bit from the host portion to form subnets. O a. 255.255.255.192, O b. 255.255.255.128, O c. 255.255.255.128, O d. 255.255.255.192, 189.166.18.0, 189.166.18.0, 189.166.18.128, 189.166.18.128, 189.166.18.63 189.166.18.127 189.166.18.255 189.166.18.255
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To solve this well first understand the original subnet mask The given subnet mask is 24 which means ...
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Computer Networking A Top-Down Approach
Authors: James Kurose, Keith Ross
7th edition
978-0133594140
