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Consider the following ARM assembly codemov r 2 , # 1 0 L: ldr r 3 , [ r 0 , # 0 ] ldr

Consider the following ARM assembly codemov r

2,

10

L: ldr r

3, [

0,

0]

ldr r

4, [

1,

0]

mul r

5,

3,

4

add r

6,

6,

5

sub r

2,

2,

1

add r

0,

0,

4

add r

1,

1,

4

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