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Consider the following function and closed interval. f (x ) = x3 - 3x+ 4, [-2, 2] Is f continuous on the closed interval [-2,

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Consider the following function and closed interval. f (x ) = x3 - 3x+ 4, [-2, 2] Is f continuous on the closed interval [-2, 2]? Yes, it does not matter if fis continuous or differentiable; every function satisfies the mean value theorem. Yes, f is continuous on [-2, 2] and differentiable on (-2, 2) since polynomials are continuous and differentiable on R. No, f is not continuous on [-2, 2]. No, f is continuous on [-2, 2] but not differentiable on (-2, 2). There is not enough information to verify if this function satisfies the mean value theorem. If f is differentiable on the open interval (-2, 2), find f'(x). (If it is not differentiable on the open interval, enter DNE.) f' ( x ) = Find f(-2) and f(2). (If an answer does not exist, enter DNE.) f( - 2) = f ( 2 ) : Find f(b) - f(@) for [a, b] = [-2, 2]. (If an answer does not exist, enter DNE.) b - a f ( b) - f(a ) b - a Determine whether the mean value theorem can be applied to f on the closed interval [-2, 2]. (Select all that apply.) Yes, the Mean Value Theorem can be applied. No, because f is not continuous on the closed interval [-2, 2]. No, because f is not differentiable on the open interval (-2, 2). No, because _(D) - () is not defined. b - a If the mean value theorem can be applied, find all values of c that satisfy the conclusion of the mean value theorem. (Enter your answers as a comma-separated list. If it does not satisfy the hypotheses, enter DNE)

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