Question
Consider the following group of bivariate values x 1 = 1.52 x 2 = 1.48 x 3 = 1.42 x 4 = 1.5 x 5
Consider the following group of bivariate values
x1 = 1.52 x2 = 1.48 x3 = 1.42 x4 = 1.5 x5 = 1.41 x6 = 1.52 x7 = 1.49
y1 = 1.44 y2 = 1.36 y3 = 1.48 y4 = 1.45 y5 = 1.3 y6 = 1.39 y7 = 1.36
Compute 6
E xiyi.
i = 1
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Differential Equations and Linear Algebra
Authors: Jerry Farlow, James E. Hall, Jean Marie McDill, Beverly H. West
2nd edition
131860615, 978-0131860612
