Consider the following half-reactions and EEvalues: Ag+(aq)+e Ag(s) E = 0.80V Cu2+(aq)+2e Cu(s) E = 0.34V Pb2+(aq)+2e Pb(s) E = -0.13V

1: Calculate the values of E, G (in kilojoules), and K for this reaction at 25C.

E =

G (in kilojoules) =

K =

2: Calculate the voltage for the cell in part (c) if both ion concentrations are 1.210² M. Express your answer using two significant figures.

Answer to Part C = Pb(s)Pb2+(aq)Ag+(aq)|Ag(s)