Consider the following neutralization reaction

CH$3$COOH$($aq$)+$ OH$-($aq$)$

CH$3$COO$-($aq$)+$H$2$O $($l$)$

For this problem two solutions are mixed. You may assume that the ending volume of the two solutions is the sum of the individual volumes. If $70\mathrm{.}1$ mL of a $0\mathrm{.}117$ mol L$-1$ acetic acid are mixed with $72\mathrm{.}6$ mL of a $0\mathrm{.}713$ mol L$-1$ sodium hydroxide fill in the ICE box below, then answer the questions that follow. Note that the units in the ICE rows are mmol.$)-$

For this problem two solutions are mixed. You may assume that the ending volume of the two solutions is

the sum of the individual volumes. If $70\mathrm{.}1mL$ of $0\mathrm{.}117mol{L}^{-1}$ acetic acid are mixed with $72\mathrm{.}6mL$ of a

$0\mathrm{.}713mol{L}^{-1}$ sodium hydroxide fill in the ICE box below, then answer the questions that follow. Note that

the units in the ICE rows are mmol.

Question $1$: The amount of acetate ion produced in mol is:

$n_{ac}=,0^8$mol

Question $2$: The concentration of the acetate ion produced in $mol{L}^{-1}$ is:

$)-$

Question $3$: The concentration of hydroxide ion after the reaction has taken place in $mol{L}^{-1}$ is:

$[$ hydroxide ion $]=,mol{L}^{-1}$

Question $10$: The concentration of sodium ion $($one of the two spectator ions$)$ is

$[Na+]=,|mol{L}^{-1}$