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Consider the following reaction: S2O42(aq)+3I(aq)+2SO42(aq)+I3(aq) (a) The rate law for this reaction is first order in 52O42(aq) and first order in I(ag). What is the

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Consider the following reaction: S2O42(aq)+3I(aq)+2SO42(aq)+I3(aq) (a) The rate law for this reaction is first order in 52O42(aq) and first order in I(ag). What is the rate law for this reaction? Rate=k1[52Oa22(ag)][1(aq)]Rate=k[S2Oa2(aq)]2(T(ac)]Pateok[52O22(aq)][I(aq)]2rate=k(S2O02(ag)]2[((oa))2Rate=k(5202)2(aq)][T(aq)]3Rate=k[5,02(oq)]4[(baq)] (b) If the rate canstant for this resction at a certain temperature is 0.00672, what is the reaction rate when (52O22(aq))=0.0445M and [1(aq)]=0.0755M. (a) The rate law for this reaction is first order in S2O32(aq) and first order in F(aq). What is the rate law for this reaction? Rate=k[S2Og2(aq)][I(aq)]Rate=k[52Og2(aq)]2[1(aq)]Rate=k[S2Og22(aq)][T(aq)]2Rate=k[52OB2(aq)]2[I(aq)]2Rate=k(52O322(aq)][1T(aq)]3Rate=k{52O22(eq)]4[I(aq)] Rate=m/s. (c) Whatis the reacison rath when tre concentration of S2O12. (aq) is doubled, to 0.0890M while the concentration of 11(aq) is 0.0755M ? Muter=N/m/s

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