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Consider the following recursive algorithm ( the same as in Question 1 ) : int f ( n ) / * n is an integer

Consider the following recursive algorithm (the same as in Question 1):
int f(n)
/* n is an integer greater than equal to 1*/
{
Let abc be the last three digits of your CWID; /* my CWID ends with 470; a=4, b=7; c=0*/
if (n==1) return c;
if (n==2) return b;
if (n==3) return a;
int x = f(n-1)+ f(n-2) ;
if (n is even and x is even) then x = x + f(n-3) ;
return x ;
};
Develop a dynamic programming algorithm that calculates and returns the same value of f(n)
for any given integer n>=1. That is, develop a dynamic programming algorithm equivalent to
the recursive algorithm f(n).
Your algorithm must be iterative and not recursive.
Describe your algorithm using C++- like syntax.

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