Consider the following set of twelve vectors in R^2: x k =[cos (/6 k) sin (/6k)] , for k = 0, 1, . . . , 11.Determine the vector v = E 11 k=0 k=6 xk. Your expression for v must be in closed formnot, for example, in terms of a sum. Hint: First determine the vector w = E 11 k=0 xk, and then infer the vector v from w. The correct answer is v = E11 k=0, k=6 xk = x1 =[1 0]. Show this