Consider the following structures and the main function shown below:

#include

#include

#include

typedef struct StringType {

char *string;

int length;

} StringType;

typedef struct Employee {

StringType *ename;

double salary;

} Employee;

Employee* createEmployees(char names[][50], double *salaries, int empCount) {

}

int main() {

const int EMPLOYEE_COUNT = 4;

//array of employees names

char nameList[][50] = {"Bill", "Mary", "Kevin", "Denise"};

//array of salaries, where 15.80 is the salary of Bill, 13.50 is

// the salary of Mary, etc.

double salaries[] = {15.80, 13.5, 20.9, 12.99};

Employee *pEmployees = createEmployees(nameList, salaries, EMPLOYEE_COUNT);

// Print Employees

int e = 0;

Employee *pEmployee = pEmployees;

printf("\tEMPLOYEE NAME\t\tSALARY ");

for (e=0;e

printf("\t%s\t\t\t%.2lf ",pEmployee->ename->string,pEmployee->salary);

pEmployee++;

}

// Deallocate memory

pEmployee = pEmployees;

for (e=0;e

free(pEmployee->ename->string);

pEmployee->ename->string = NULL;

free(pEmployee->ename);

pEmployee->ename = NULL;

pEmployee++;

}

free(pEmployees);

pEmployees = NULL;

return 0;

}

Write a function createEmployees() that takes the list of employees' names, list of their salaries, and

length of the list (empCount) as the parameters, and returns a pointer to a dynamically allocated array

of Employee storing the relevant information for empCount employees.

The function dynamically allocates memory for empCount number of employees and assigns the name

and salaries for each of them from the input parameters. During this process, the names are stored in

the dynamically allocated memory of StringType, and also make sure you assign the length of the name

appropriately. Your code should use exact amount of memory needed to store the corresponding

names. You may assume no name is longer than 49 characters.

Employee* createEmployees(char names[][50], double *salaries, int empCount)