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Consider the functions z = 6 e x l n ( u c o s v ) and y = u s i n v
Consider the functionsz=6exln(ucosv) and y=usinv.
a)Expressuz andvz as function of u and v both by using the Chain Rule and by expressing z directly in tems of u and v before differentiating
b) Evaluateuz andvz at (u,v)=(5,4)
(a) Find each partial derivative needed to use the Chain Rule to finduz
xz= yz=
ux= uy=
Express z directly in terms of u and v.
z=
Using either method,uz=
Find each partial derivative needed to use the Chain Rule to findvz
xz= vx=
yz= vy=
Using either method,vz=
b)uz(5,4)=
vz(5,4)=
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