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Consider the NAND operator uparrow, which is defined p uparrow q (p Lambda q). Using truth tables show that uparrow is not associative, i.e., p

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Consider the NAND operator uparrow, which is defined p uparrow q (p Lambda q). Using truth tables show that uparrow is not associative, i.e., p uparrow (q uparrow r) and (p uparrow q) uparrow r are not equivalent

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