Consider the process of Cd(s)+Br2(l)CdBr2(s). a. Assuming that cadmium (II) bromide forms a perfect crystal with a sodium chloride structure (A=1.763), calculate its lattice energy using the lattice energy equation below. The ionic radius of the Mg2+ ion is 0.097nm and that of the O2 ion 0.196nm. b. Draw the Born-Haber Cycle for CdBr2. c. Given the following information for Cd,Br, and CdBr2, calculate the lattice energy CdBr2. for Cd(s),Hsub=+111.9kJ/mol - for Br2(l),Hvap=+30.9kJ/mol - Ist IE for Cd=+870kJ/mol - Ist EA for Br=342kJ/mol 2nd IE for Cd=+1600kJ/mol - For CdBr2(s),Hr=314.6kJ/mol - Bond dissociation energy for O2=+193 kJ/mol