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Consider the reaction of ethyl bromide with sodium hydroxide: CH3CH2Br(aq)+NaOH(aq)CH3CH2OH(aq)+NaBr(aq) The reaction is first order in NaOH and second order overall. What is the rate

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Consider the reaction of ethyl bromide with sodium hydroxide: CH3CH2Br(aq)+NaOH(aq)CH3CH2OH(aq)+NaBr(aq) The reaction is first order in NaOH and second order overall. What is the rate law? View Available Hint(s) rate=k[CH3CH2Br]2[NaOH]2rate=k[CH3CH2Br][NaOH]2rate=k[NaOH]rate=k[CH3CH2Br]rate=k[CH3CH2Br][NaOH]rate=k[CH3CH2Br]2[NaOH]

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