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Consider the region enclosed by the graphs of 2y = 3,y = 6, and 2y + 4x = 7. The area A of this region

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Consider the region enclosed by the graphs of 2y = 3,y = 6, and 2y + 4x = 7. The area A of this region could be computed in two ways: 1) By integrating with respect to x, A = f: h1(x) dx + f; hz (x) dx where a = , b = , C = , him = ,and 1w) = The area A = 2) By integrating with respect to y, A = f; 113 (y) dy whered = . e = ,and ]13 0') = The area A = Sketch the region enclosed by the curves x = 4y and x = y + 6. List the points of intersection of these curves from BOTTOM to TOP in the form (x, y) : ) and ( Decide whether to integrate with respect to x or y to find the area A of this region. A =Consider the region between the graphs x = y2 7 and x + 1y = 5 . The area of this region can be computed as f: 1107) dy where a = , b = and h(y) = The area is

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