Consider the signal x[n] = delta[n] + 2 delta[n - 1] + 3 delta [n - 2]. Consider now its moving average, i.e. the signal y[n] = 1/2(x[n] + x[n- 1]) Select the correct expressions from the options below. y[n] = 0.5 delta[n] + 1.5 delta[n - 1] + 2.5 delta [n - 2] + 1.5 delta[n - 3]. The output for n greaterthanorequalto 0 is always zero