Consider the topology shown in the Figure below. Denote the three subnets with hosts as Networks A$,$ B$,$ and C$.$ Denote the subnets without hosts as Networks D$,$ E$,$ and F$.$

a$.$ Assign network addresses to each of these six subnets, with the following constraints: All addresses must be allocated from $200\mathrm{.}150\mathrm{.}246/23$; Subnet A should have enough addresses to support $250$ interfaces; Subnet B should have enough addresses to support $120$ interfaces; and Subnet C should have enough addresses to support $120$ interfaces. Of course, subnets D$,$ E and F $($interior subnets for routers$)$ should each be able to support two interfaces. For each subnet, the assignment should take the form a$.$b$.$c$.$d$/$x$.$

b$.$ Using your answer to part $($a$),$ provide the forwarding tables $($using longest prefix matching$)$ for each of the three routers HEY TEACHER COULD YOU PLEASE EXPLAIN IT IN DETAILS AND MORE EASY WAY $,$ THANK YOU