Consider this example provided by my teacher:

2. Solve log3 x + log3 (5x - 6) = 3 Product Property logb (F L) = logDF + logbL log3 x (5x - 6) = 3 logbN = x log28 = 3 bx = N 23 = 8 log3 x (5x - 6) = 3 33 = x(5x - 6) 27 = 5x2 - 6x 0 = 5x2 - 6x - 27 -135 5x2 - 6x - 27 = 0 -15 +9 5x2 - 15x + 9x - 27 = 0 -6 5x(x - 3) +9(x - 3) = 0 (x - 3) (5x + 9) = 0 (x - 3) =0 (5x + 9) = 0 x = 3 X = - X= - is extraneous is extraneous2. Solve logs x + logs (3x - 10) = 2