Considering the following MIPS code:$$begin:

loop:

finish:

addi $t$0,$ $zero, $22$ move $t$1,$ $zero

li $a$0,0$

beq $t$0,$ $t$1,$ finish add $t$1,$ $t$1,$ $a$0$ addi $t$0,$ $t$0,-4$ addi $a$0,$ $a$0,1$

j loop