construction accounting problem

A selection must be made in regard to two cash flow diagrams below on the basis of equivalent annual worth. At an interest rate of 10% the equation that must be used to make this selection is? AWA=200,000(A/P,12%,6)20,000+65,000(A/F,12%,6) and AWB=150,000(A/P,12%,4) 35,00020,000(P/F,12%2)(A/P,12%4)+15,000(A/F,12%,4) PWA=200,00020,000(P/A,10%,6)+65,000(P/F,12%,6) and PWB=150,00035,000(P/A, 10%,4)20,000(P/F,12%2)+15,000(P/F,12%,4) FWA =200,000(F/P,10%,6)20,000(F/A,10%,6)+65,000 and PWB=150,000(F/P,10%,4) 35,000 (F/A, 10%,4)20,000(F/P,12%2)+15,000 AWA=200,000(A/P,12%,6)20,000+65,000(A/F,12%,6) and AWB=150,000(A/P,12%,4) 35,00020,000(A/F,12%2)+15,000(A/F,12%,4) A selection must be made in regard to two cash flow diagrams below on the basis of equivalent annual worth. At an interest rate of 10% the equation that must be used to make this selection is? AWA=200,000(A/P,12%,6)20,000+65,000(A/F,12%,6) and AWB=150,000(A/P,12%,4) 35,00020,000(P/F,12%2)(A/P,12%4)+15,000(A/F,12%,4) PWA=200,00020,000(P/A,10%,6)+65,000(P/F,12%,6) and PWB=150,00035,000(P/A, 10%,4)20,000(P/F,12%2)+15,000(P/F,12%,4) FWA =200,000(F/P,10%,6)20,000(F/A,10%,6)+65,000 and PWB=150,000(F/P,10%,4) 35,000 (F/A, 10%,4)20,000(F/P,12%2)+15,000 AWA=200,000(A/P,12%,6)20,000+65,000(A/F,12%,6) and AWB=150,000(A/P,12%,4) 35,00020,000(A/F,12%2)+15,000(A/F,12%,4)