Continuing under the code for part 1.b, you are going to add code to test and then print each letter of your name IF the letter is a consonant. For purposes of this part of the code, please use your name in English alphabet letters only. We are going to put your name in a string and then write conditional statements to check each letter of your name in the string.

If the letter being checked is a consonant, then we will print it, if not, we will skip it.

This part of the program will have a bunch of repeated chunks of code, i.e. a few lines of code that will look very much the same will be used over and over again for as many letters as you have in your name.

First declare a character array, a C string, that holds your name; i.e. create and initialize a string that holds your family name. (Again, make sure you are using a name with at least 6 letters in it.). Name this string variable fName. Using the function iscons (below), write a test for the first letter in fName, the oth element, to see if it is a consonant.

If iscons(fName[0]) returns a 1, then the letter at fName[0] is a consonant. If the function call returns a 0, then the letter is a vowel. Print each consonant and their Unicode code together as a pair on one line. After you have tested the first letter at location [O] (and printed or not), then write the same test for the second letter at location [1] and print that letter and its code if it is a consonant. Do this for all remaining letters.

This will give you multiple small blocks of code that look the same except for testing a different letter from fName. Each pair of consonants and Unicode codes should be on a separate line.

For this part of the assignment do NOT implement a loop. The code for the function iscons should be put at the bottom of the program after the closing curly brace in main. You will also need to put the line : int iscons (char ltr); above the beginning of the main function in order for C to correctly define iscons.

Copy this function iscons after your main routine in your.c file: Il tests whether it is a consonant in the English alphabet int iscons (char ltr) { ltr = tolower(ltr); // // be sure to #include if ((ltr == 'a') || (ltr 'e') || (ltr == 'i') IL (ltr == 'o') || 'o') || (ltr 'u')) return 0; return 1; } = == == Take one screenshot of the lines of code that implement these actions and take a 2nd screenshot of your output. NOTE: You'll now have the four lines of output from 1.a. and part 1.b, then the rows of letter, Unicode code combinations.

Rubric: {9 pts} Correct C code for test to determine if the current letter is a consonant {3 pts} Correct use of letter at each location fName[#] to test (1 pts} Correct C code to print one letter and one ASCII code on each line of a table making two columns {3} Output screenshot(s) show correct information {2 pts} Example output (showing only the new output lines added.

This is not the entire required output) 80 P 80 h 104 h 104 114 114 115 115 t 116 116 r r S S t