Convert the following NFA with epsilon moves to an equivalent NFA without epsilon moves where the starting state is $q_0$ and final state is $q2.$

$\backslash$table$[[$States$/$input$,\backslash$epsi $,$a$,$b$,$c$],[$q$^(0),\backslash$Phi $,\{$q$0\},\{$q$1\},\{$q$2\}],[$q$^(1),\{$q$0\},\{$q$1\},\{$q$^(2)\},\backslash$Phi $],[$q$^(2),\{$q$1\},\{$q$2\},\backslash$Phi $,\{$q$0\}]]$