Convert the following numbers from the given number system to the required number system. Hint: to convert between any two number systems that none of them is decimal you can convert to decimal first and then to the final required number system - excluding conversions between binary and hexadecimal (base 16) which is easier to be done directly 1. 82.75,0 to binary number system 2. 82.75,0 to hexadecimal number system (base 16 number system) 3. 89.26 to binary number system 4. 89.216 to decimal number system 5. 519,0 to base 5 number system 6: 51910 to base 4 number system 7. 51910 to base 3 number system 8. 519.0 to binary number system 9. 27110 to hexadecimal number system 10, 271, to binary number system 11. 2345 to base 3 number system 12. 1002, to base 5 number system 13. 129,0 to base 5 number system 14. 129.0 to base 8 number system 15. 129,0 to base 5 number system 16. 129,0 to hexadecimal number system 17. 100011, to decimal number system 18. 100011, to hexadecimal number system 19. 10011001.011, to decimal number system 20. 10011001.011, to hexadecimal number system (12 points) Problem #2 Add in binary: 10010110 + 100111 Subtract in binary: 10000000 - 101 Multiply in binary: 101100 x 1101 Divide in binary: 11010001 - 1011 Problem #3 (10 points) Assume negative number representation systems with 7 bits word length (word length is the number of digits or bits used to represent a number including the sign digit). Perform the following tasks. if it is not possible to find the answer because of limited number of digits (overflow), write N/A 1. In sign and magnitude binary representation, 4110 is 2. In 2's complement binary representation, -2910 is 3. In l's complement binary representation, - 2920 is 4. Using 2's complement representation, we can represent any number between N1 = ....... and N2 (write the answers in decimal) 5. Using is complement representation, we can represent any number between N1 = ....... and .... (write the answers in decimal) 6. in 2's complement, N, = 1001001, and N, = 01011002. Ny + N2 = (in binary) 7. In 1's complement, N, = 1001001, and N, = 01011002. N+ N2 = ........ (in binary) 8. In 2's complement, N, = 0111101, and N, = 01011012. NA + N2 = (in binary) N2 =... Problem #4 (8 points) 1. Write 806.73 in 8-4-2-1 Code (BCD) Excess - 3 Code 6-3-1-1 Code 2. Is it possible to construct a 6-4-1-1 weighted code? Justify your