Convert the following relational algebra statements to SQL:

$10.$ student

$11.\backslash$Pi name$($student$)$

$12.\backslash$sigma gpa$=3\mathrm{.}0($student$)$

$13.$ studentXtakes

$14.$ student $./$ takes

$15.\backslash$sigma dept$=$CS$$gpa$>3\mathrm{.}0($student$)$

$16.\backslash$Pi name$(\backslash$sigma gpa$>2\mathrm{.}0($student$)\backslash$cup $\backslash$Pi title$(\backslash$sigma dept$=$CS$($prof essor$))$