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Could someone help me with this please We illustrate this method with an example. Example 7.3. Apportion h = 10 seats to n = 3

Could someone help me with this please

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We illustrate this method with an example. Example 7.3. Apportion h = 10 seats to n = 3 states with populations P1 = 264, p2 = 361, and p3 = 375. The total population p is 264 + 361 + 375 = 1000, so the standard divisor is s = p/h = 1000/10 = 100. This indicates that there is one representative for every 100 people across the three states, so an ideal district would have precisely 100 residents. When the standard divisor is a round number like this, the computations are particularly simple. The standard quotas are obtained by dividing the state populations by the standard divisor s. We obtain q1 = 2.64, q2 = 3.61, and q3 = 3.75 for the three states. The lower quotas are 2, 3, and 3, respectively. According to Hamilton's method, we provisionally apportion 8 of the 10 seats in the House according to these lower quotas. Two seats remain unassigned, and we give them to the two states the fractional part of whose standard quota is largest. These fractional parts are 0.64, 0.61, and 0.75, so it is the first and the third states that get extra seats. These states are both assigned their upper quota instead of their lower quota. The final Hamilton apportionment is therefore a1 = 3, a2 = 3, and a3 = 4. The process is summarized in the Table 7.1. Hamilton's Method 139 Table 7.1 Working out Hamilton's method. Fractional Part Hamilton Standard Lower Upper of Standard Apportion- Pk Quota Quota Quota Quota ment 264 2.64 2 3 0.64 3 2 361 3.61 3 0.61 3 3 375 3.75 3 4 0.75 4 p = 1000 h = 10 Hamilton's method is the first method one can imagine, and it might be regarded as the obvious one. In fact, at first it is difficult to imagine any other way to solve an apportionment problem. You simply round every state's fair share up or down, rounding up the states that are closer to their upper quotas, naturally. What could be wrong with that? Plenty, it turns out

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