Could someone please verify if my data chart is correct, and if not, can someone fix it ? thank you !!

4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 212 23 24 25 26 wo ww le I JOHNSON LEVEL & TOOL MFG. CO. INC. OL 19 S 4 3 21 8ths Ray Diagram for Part ( 9 ) : Of = 20 0m 1 = 360m 300 mm toomm do = 200 mm di = 120 mm *= 360 MM IMAGE 420 mm * = 200 mm OBJECT Af-loommOne lens with focal length, f = 100mm do, mm di, mm ho hi Mn M d Experiment 19 mm 17.78 mm 0.9357 mm - 0.60 mm 200 mm 120 mm Calculations 0.005 mm 0.008 mm 0.052 mm 0.056 mm 0.1088 mm 0.013 mm Ray diagram 300 mm -450 mm 100 mm 420 mm 22.1 mm 2.25 m Changing do di, mm ho hi Mn Ma do, mm Measured Calculated Measured Measured Calculated 1.05 mm -4.50 mm -1.28 mm 140 mm 180 mm 350 mm 19 mm 20 mm 1.74 mm -2.2 mm 100 mm 220 mm Infinity 19mm 33mm -1.83 mm 70 mm 250 mm -233.33 mm 19mm 37 mm 1.95 mm -1.38 mm -3.57 mm 40 mm 280 mm -66.66 mm 19mm 38 mm 2 mm -1.16 mm -7 mm 180 mm 140 mm 225 mm 19mm 14 mm 0.74 mm -3.50 mm 0.78 mm\fThe object distance, focal length and image distance for a thin lens are related by thin lens equation. (2) The magnification of the image, M, is M = h; h d.f do do f z = did - f2 (5) f 2 Equation 5 allows us to find the final image distance value for the two-lens system. The orientation and size of the final image can be found as follows: The total magnification produced by a lens system is equal to the product of the magnifications produced by each lens individually. Using Equation 3, we find that the first lens produces thedi -. The total di .Similarly, the second lens causes the magnification M = - magnification M = -- do The object distance, focal length and image distance for a thin lens are related by thin lens equation. (2) d The magnification of the image, M, is h; M = h d d. def (5) = d = d f2 do - f2 Equation 5 allows us to find the final image distance value for the two-lens system.The orientation and size of the final image can be found as follows: The total magnification produced by a lens system is equal to the product of the magnifications produced by each lens individually. Using Equation 3, we find that the first lens produces the magnification M = --. Similarly, the second lens causes the magnification M' = - The total d. magnification of the system, then, is m = MM', showing that the final image is inverted if m0, and changed in size by a factor of m compared with the original object. This value must be in agreement with the results obtained in experiment where the magnification can be found from formulae: M = hi M' = hu ho ho' m = MM' and ho' = hi- Calculated value - Experimental value D = . 100% Calculated value