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could you please answer the question! thanks!! The average salary for a certain profession is $66500. Assume that the standard deviation of such salaries is

could you please answer the question! thanks!!

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The average salary for a certain profession is $66500. Assume that the standard deviation of such salaries is $38,000. Consider a random sample of 73 people in this profession and let x represent the mean salary for the sample. Click the icon to view the table of normal curve areas. a. What is ;? HE b. What is o? (Round to 2 decimal places as needed.) C. Describe the shape of the sampling distribution of x. O A. The shape is that of a poisson distribution. OB. The shape is that of a uniform distribution. OC. The shape is that of a normal distribution. OD. The shape is that of a binomial distribution. d. Find the 2-score for the value x = 57,000. Z= (Round to 2 decimal places as needed.) e. Find P(X> 57,000) P(x>57,000) - Normal curve areas ht the mean salary for the sample. The average salary for a certain profession Click the icon to view the table of norn a. What is ;? 0 HE Z z .00 .01 .02 .03 .04 .07 .08 .09 b. What is o? .0 .1 .2 .3 .4 .5 .0040 .0438 .0832 .1217 .1591 .1950 .2291 .0120 .0517 .0910 .1293 .1664 2019 .05 .0199 .0596 .0987 .1368 .1736 .2088 .0279 .0675 .1064 .1443 .1808 .2157 0- .0080 .0478 .0871 .1255 .1628 .1985 .2324 .2642 .2939 .3212 .3461 .0319 .0714 .1103 .1480 .1844 .2190 oj (Round to 2 decimal places as .06 0239 .0636 .1026 .1406 .1772 .2123 .2454 .2764 .3051 .3315 .3554 C. Describe the shape of the sampling e12345 6789m 12:15 &A .0000 .0398 .0793 .1179 .1554 .1915 2257 .2580 .2881 .3159 .3413 .3643 .3849 .4032 4192 .4332 4452 .4554 .4641 4713 .4772 .0359 .0753 .1141 .1517 .1879 2224 2549 2852 .3133 .3389 .3621 2611 .2910 .3186 .3438 .0160 .0557 .0948 .1331 .1700 .2054 .2389 .2704 .2995 .3264 .3508 .3729 .3925 4099 .4251 .4382 .4495 .4591 .4671 .4738 .4793 .2422 .2734 .3023 .3289 .3531 O A. The shape is that of a poisson distr OB. The shape is that of a uniform distri O C. The shape is that of a normal distri OD. The shape is that of a binomial dist| .2486 .2794 .3078 .3340 .3577 .2517 .2823 .3106 .3365 .3599 1.3 1.4 .3686 .3888 4066 4222 .4357 .2357 .2673 2967 .3238 .3485 .3708 .3907 .4082 4236 .4370 .4484 .4582 .4664 .4732 .4788 .3810 .3997 .4162 .4306 .4429 .3665 .3869 4049 4207 .4345 .4463 .4564 4649 .4719 .4778 .3830 4015 4177 4319 4441 .3749 .3944 4115 .4265 .4394 4505 .4599 .4678 .4744 .4798 .3770 .3962 .4131 .4279 .4406 4515 .4608 .4686 .4750 .4803 .3790 .3980 4147 .4292 4418 .4525 .4616 .4693 4756 .4808 d. Find the 2-score for the value x = 57|| 1.6 1.7 1.8 1.9 2.0 .4474 .4573 .4656 .4726 .4783 .4535 .4625 .4699 .4761 .4812 4545 4633 4706 4767 4817 Z= (Round to 2 decimal places as e. Find P(X> 57,000) P(x>57,000) = 0 Print Done

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