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Could you please fill out this scheme? ;;; predicates: list? null? eq? equal? ;;; quote ;;; car cdr caddr ;;; cons list append ;;; length

Could you please fill out this scheme? ;;; predicates: list? null? eq? equal? ;;; quote ;;; car cdr caddr ;;; cons list append ;;; length (newline) (display (cons 0 '(1 2 3)))(newline) (display (cons '(a b) '(1 2 3)))(newline) (display (cons (+ 10 20) '(1 2 3)))(newline) (display (list '(a) '(b c d)))(newline) (display (append '(a) '(b c d)))(newline) (display (cdadr '((1 2) (3 4) (5 6))))(newline) (display (list (+ 2 3) 0))(newline) (display (list '(+ 2 3) 0))(newline) (display (cons (car '(1 2 3)) (list 'a 'b 'c)))(newline) (display (append '(1 2 3) (list 'a 'b 'c)))(newline) (define (length lst) (cond ((null? lst) 0) ((list? lst) (+ 1 (length (cdr lst)))) (else 0) ) ) (define (maxelt lst) (if (= (length lst) 1) (car lst) (max (car lst) (maxelt (cdr lst)))) ) (define (minelt lst) (if (= (length lst) 1) (car lst) (min (car lst) (minelt (cdr lst)))) ) (define (numzeros lst) ; fill this in 0 ) (newline) (display "Testing numzeros")(newline) (display (numzeros `()))(newline) ; expect 0 (display (numzeros `(0)))(newline) ; expect 1 (display (numzeros `(0 0)))(newline) ; expect 2 (display (numzeros `(1 0 1 0 1 0)))(newline) ; expect 3 (display (numzeros `(1 1 1 1)))(newline) ; expect 0 (define (randlist len) (if (= len 0) '() (cons (random 100) (randlist (- len 1)) ) ) ) (define (allbutlast lst) ; complete. return original list, but without the last element ; lst should never be empty (no need to check for that) '() ) (newline) (display "Testing allbutlast")(newline) (display (allbutlast '(1 2 3 4 5)))(newline) ; expect (1 2 3 4) (display (allbutlast '(1)))(newline) ; expect (1 ) (define (ismember atm lst) (cond ((null? lst) #f) ((equal? atm (car lst)) #t) (else (ismember atm (cdr lst))) ) ) (define (odds lst) (cond ((null? lst) '()) ((odd? (car lst)) (cons (car lst) (odds (cdr lst)))) (else (odds (cdr lst))) ) ) (define (minandmax lst) ; fill this in. return (min, max) '(0 0) ) (newline) (display "Testing minandmax")(newline) (display (minandmax `( 1 2 3 4 5)))(newline) ; (1 5) (display (minandmax `( 5 4 3 2 1)))(newline) ; (1 5) (display (minandmax `( 5)))(newline) ; (5 5) (display (minandmax `( 5 -5 3 -3 2 -2 1 -1 0)))(newline) ; (-5 5) (define (zip lst1 lst2) ; fill this in ; input is two simple lists of same length: (1 2 3 4) (a b c d) ; returns ((1 a) (2 b) (3 c) (4 d)) '() ) (newline) (display "Testing zip")(newline) (display (zip '(1 2 3 4) '(a b c d)))(newline) (define (remove v lst) (cond ((null? lst) '() ) ((= v (car lst)) (cdr lst)) (else (cons (car lst) (remove v (cdr lst)) ) ) ) ) (define (sort lst) (if (null? lst) '() (cons (minelt lst) (sort (remove (minelt lst) lst))) ) ) 

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