Question
CRA CDs Inc. wants the mean lengths of the cuts on a CD to be 126 seconds (2 minutes and 6 seconds). This will allow
CRA CDs Inc. wants the mean lengths of the "cuts" on a CD to be 126 seconds (2 minutes and 6 seconds). This will allow the disk jockeys to have plenty of time for commercials within each 10-minute segment. Assume the distribution of the length of the cuts follows the normal distribution with a population standard deviation of 7 seconds. Suppose we select a sample of 15 cuts from various CDs sold by CRA CDs Inc. |
a. | What can we say about the shape of the distribution of the sample mean? |
Sample mean | (Click to select)BinomialUniformNormal |
b. | What is the standard error of the mean?(Round your z-value to 2 decimal places and final answer to 2 decimal places.) |
Standard error of the mean | seconds. |
c. | What percent of the sample means will be greater than 128 seconds?(Round your z-value to 2 decimal places and final answer to 2 decimal places.) |
Percent | % |
d. | What percent of the sample means will be greater than 120 seconds?(Round your answer to 2 decimal places.) |
Percent | % |
e. | What percent of the sample means will be greater than 120 but less than 128 seconds?(Round your z-value to 2 decimal places and final answer to 2 decimal places.) |
Percent | % |
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