Question
CREATE TABLE customer ( customer_id INTEGER NOT NULL, customer_name VARCHAR (25) NOT NULL, address_line_1 VARCHAR (200), city VARCHAR (100), state_province CHAR (25), postal_code VARCHAR (50),
CREATE TABLE customer ( customer_id INTEGER NOT NULL,
customer_name VARCHAR (25) NOT NULL,
address_line_1 VARCHAR (200),
city VARCHAR (100),
state_province CHAR (25),
postal_code VARCHAR (50),
PRIMARY KEY (customer_id) ) ;
CREATE TABLE order_header ( order_id INTEGER NOT NULL,
order_date DATE,
customer_id INTEGER,
PRIMARY KEY (order_id),
CONSTRAINT order_fkey_customer_id FOREIGN KEY (customer_id) REFERENCES customer (customer_id)) ;
CREATE TABLE product ( product_id INTEGER NOT NULL,
product_name VARCHAR (200),
product_line VARCHAR (200),
product_price DECIMAL(19,2),
PRIMARY KEY (product_id) ) ;
CREATE TABLE order_line ( order_id INTEGER NOT NULL,
product_id INTEGER NOT NULL,
quantity INTEGER,
PRIMARY KEY (order_id,
product_id),
CONSTRAINT order_line_fkey_order_id FOREIGN KEY (order_id) REFERENCES order_header (order_id),
CONSTRAINT order_line_fkey_product_id FOREIGN KEY (product_id) REFERENCES product (product_id)) ;
Create a query that uses a Common Table Expression (CTE) and a Window Function to find the last (most recent) customer in each city to place an order. Your query should return the following columns:
-- last_customer_name (split the name into first and last names, use the last name)
-- city
-- (Hints: Try the RANK function. Make sure to handle customers with 3 names. )
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