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csv file ,Sample_1,Sample_2 1,139,71 2,147,89 3,141,114 4,169,77 5,156,92 6,160,122 7,167,122 8,139,111 9,140,120 10,165,85 11,144,58 12,169,118 13,150,109 14,142,84 15,143,120 16,171,104 17,117,88 18,157,110 19,155,95 20,159,115 21,122,122 22,159,126
csv file
"","Sample_1","Sample_2" "1","139",71 "2","147",89 "3","141",114 "4","169",77 "5","156",92 "6","160",122 "7","167",122 "8","139",111 "9","140",120 "10","165",85 "11","144",58 "12","169",118 "13","150",109 "14","142",84 "15","143",120 "16","171",104 "17","117",88 "18","157",110 "19","155",95 "20","159",115 "21","122",122 "22","159",126 "23","144",115 "24","149",94 "25","143",77 "26","168",130 "27","151",111 "28","151",74 "29","147",114 "30","176",94 "31","",121 "32","",82Problem 5. PREVIEW ONLY -- ANSWERS NOT RECORDED (4 points) random number generator was used to produce two samples from a Nomal distribution. The samples can be found here: sample 1: 139, 147, 141, 169, 156, 160, 167, 139, 140, 165, 144, 169, 150, 142, 143, 171, 117, 157, 155, 159, 122, 159, 144, 149, 143, 168, 151, 151, 147, 176 sample 2: 71, 89, 114, 77, 92, 122, 122, 111, 120, 85, 58, 118, 109, 84, 120, 104, 88, 110, 95, 115, 122, 126, 115, 94, 77, 130, 111, 74, 114, 94, 121, 82 Download .csv file Use a = 0.048 as the level of significance for any tests you use in this question. According to what you know about sample 1, when performing a hypothesis test of normality, what can you conclude? A. An error has occured but since the sample is larger than 25, the distribution is automatically normal (because of CLT) B. A type Il error has occured C. No error has occured the sample is normally distributed D. A type l error has occured E. No error has occured the sample is not normally distributed Complete the interpretation of the P-value computed in nomaility test above: Assuming Hois ? , the probability of ? null hypothesis is (use three decimals in your answer). Complete the interpretation of the P-value computed in normality test above: the probability of ? null hypothesis is . (use three decimals in your answer). Assuming H. V ? false uncertain true Entered Answer Preview Complete the interpretation of the P-value computed in normaility test above: Assuming H, is ? the probability null hypothesis is (use three decimals in your answer). ? observing stronger evidence to support the rejecting the failing to reject the observing stronger evidence against the Entered Answer Preview Problem 5. PREVIEW ONLY -- ANSWERS NOT RECORDED (4 points) random number generator was used to produce two samples from a Nomal distribution. The samples can be found here: sample 1: 139, 147, 141, 169, 156, 160, 167, 139, 140, 165, 144, 169, 150, 142, 143, 171, 117, 157, 155, 159, 122, 159, 144, 149, 143, 168, 151, 151, 147, 176 sample 2: 71, 89, 114, 77, 92, 122, 122, 111, 120, 85, 58, 118, 109, 84, 120, 104, 88, 110, 95, 115, 122, 126, 115, 94, 77, 130, 111, 74, 114, 94, 121, 82 Download .csv file Use a = 0.048 as the level of significance for any tests you use in this question. According to what you know about sample 1, when performing a hypothesis test of normality, what can you conclude? A. An error has occured but since the sample is larger than 25, the distribution is automatically normal (because of CLT) B. A type Il error has occured C. No error has occured the sample is normally distributed D. A type l error has occured E. No error has occured the sample is not normally distributed Complete the interpretation of the P-value computed in nomaility test above: Assuming Hois ? , the probability of ? null hypothesis is (use three decimals in your answer). Complete the interpretation of the P-value computed in normality test above: the probability of ? null hypothesis is . (use three decimals in your answer). Assuming H. V ? false uncertain true Entered Answer Preview Complete the interpretation of the P-value computed in normaility test above: Assuming H, is ? the probability null hypothesis is (use three decimals in your answer). ? observing stronger evidence to support the rejecting the failing to reject the observing stronger evidence against the Entered Answer Preview
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