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Current Attempt in Progress Examine the enthalpy diagram below and correctly place the enthalpy changes for a one-step conversion of germanium, Ge(5), into GeO2(s), the

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Current Attempt in Progress Examine the enthalpy diagram below and correctly place the enthalpy changes for a one-step conversion of germanium, Ge(5), into GeO2(s), the dioxide. On this same diagram, show the two-step process, first to the monoxide, GeO(s), and then its conversion to the dioxide. The relevant thermochemical equations are the following: Ge(s) + 702(8) + GeO(s) AH =-255 kJ Ge(s) + 02(g)- GeO, (s) AH.=-534.7 kJ a b d f GeO2(5) GeO(s) + 1202(g) Ge(s) + 02(5) -534.7 kJ -255 kJ The letter v, refers to AH for the following reaction: GEO(s) + 702(g)- GeO2 (5) Determine AH" for this reaction. i KJ1/0 -5 1.0 5 a) On what intervals is f() increasing? On what intervals is f() decreasing? b) Does f(x) have local maxima or minima? If so, which and where? (If none, enter 'DNE' in the appropriate box.) Local maxima at ~ = Local minima at ~ = c) Does f() have any inflection points? If so, where are they? (Estimate to the nearest tenths place. If none, enter 'DNE' in the box below.) Inflection points at c =The amino acid glycine, C2HsNO2, is one of the compounds used by the body to make proteins. The equation for its combustion is 4C2H;NO2(s) + 902(g) - 8CO2(g) +10H20(1) +2N2(5) For each mole of glycine that burns, 973.49 kJ of heat is liberated. Use this information, plus values of AH, for the products of combustion, to calculate AH," for glycine. i ! KJ/mol(1 point) Find a formula for a function of the form y = bre "with a local maximum at (7, 4). 0 = =1 point} (This problem is similar to workbook problems on Global Extrema problem 1} _ 3 2 .et z) 22: 4.53 1. a. On the interval [3, 3.5], the global minimum is E and the the global maximum is b. On the interval [1, 4-5], the global minimum is .:: and the the global maximum is E: c. On the interval [9, 1.5], the global minimum is 55 . and the HIE global maximum i5 {1 point) {This problem is similar to workbook problem 1 of Global Extrema) Let x) = :3 21:2 + 144:: 3. On the interval [9, 11], the global minimum of x) is and the the global maximum of x) is (1 point) Find the global minimum and maximum value of the functions on the intervals given. If the given global extremum does not exist, enter 'DNE' into the appropriate box. a) sin(x) + x on [72 , ;] Global Maximum: Global Minimum: b) v 3 + 1 on [0, 4] Global Maximum: Global Minimum: c) x + = on (0, 00) Global Maximum: Global Minimum: HE(1 point) Consider the function f(t) = the "where b is some constant and t > 0. a) For what value of b > 0 will f(t) have a local extremum at t = 6? b) Is this a local maximum or minimum? c) Is it a global extremum? d) What is lim f(t)? 1 100 lim f(t) = e) (Activity) Use all of the information you have obtained about f to sketch a graph of f.(1 point) Find the best possible (lower and upper) bounds for the function f(@) = x + sin(@) on the interval [10%, 12x]. Upper bound: Lower bound:(1 point) Consider the function f (t) = - 2t 14 50 ) What are the local extrema? (Enter your answer as a list of numbers.) Local extrema: ) What are the global extrema? (Enter your answer as a list of numbers.) Global extrema: ") What is lime to f(t)? lime woo f(t) = d) What is lime , co f(t)? lime > co f (t) = e) Based on your answers to parts a) through d), select the graph which best represents the function f. OA. Graph 3 OB. Graph 4 O C. Graph 1 OD. Graph 2 1.0 Graph 1 Graph 2 1/0 Graph 3 Graph 4(1 point) For each of the parts below, give your answer as a list of ordered pairs in terms of a and 6. If there is answer for an individual part, enter NONE. a) Suppose that a > 0 and b > 0. Consider the function f(x) = = + bx for x / 0. Find the critical points and local extrema of f in terms of a and b, Critical points: Local maxima: Local minima: b) Now suppose that a 0 and b 0, and again consider the function f(x) = 4 + bx for x / 0. Find the critical points and local extrema of f in terms of a and b. Critical points: Local maxima: Local minima

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