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Current technology uses high-resolution X-rays and lasers for inspection of solder-joint defects on printed circuit boards (PCBs). Aparticular manufacturer of laser-based inspection equipment claims that
Current technology uses high-resolution X-rays and lasers for inspection of solder-joint defects on printed circuit boards (PCBs). Aparticular manufacturer of laser-based inspection equipment claims that its product can inspect on average at least 10 solderjoints per second when the joints are spaced 0.1 inch apart. The equipment was tested by a potential buyer on 48 different PCBs. In each case, the equipment was operated for exactly '1 second. The numbers of solderjoints inspected on each run are shown in the accompanying data table. Complete parts a through 0. Click the icon to View the data. A Type I error would be to conclude that the sample mean number of solder joints inspected is greater than 10 when, in fact, the mean is equal to 10. A Type I error would be to conclude that the true mean number of solderjoints inspected is less than '10 when, in fact, the mean is equal to 10. A Type I error would be to conclude that the true mean number of solderjoints inspected is not equal to 10 when, in fact, the mean is equal to 10. A Type I error would be to conclude that the true mean number of solderjoints inspected is equal to 10 when, in fact, the mean is less than 10. Now identify what a Type II error is for this situation. Choose the correct answer below. V AType ll error would be to conclude thatthe true mean number of solderjoints inspected is 10 when, in fact, the mean is less than '10. A Type II error would be to conclude that the true mean number of solder joints inspected is not equal to 10 when, in fact, the mean is equal to 10. A Type II error would be to conclude that the true mean number of solder joints inspected is less than 10 when, in fact, the mean is equal to 10. A Type II error would be to conclude that the sample mean number of solderjoints inspected is 10 when, in fact, the mean is greater than 10. (2. Conduct the hypothesis test you described in part a and interpret the test's results in the context of this exercise. Use a = 0.10. Calculate the value of the test statistic. Z: (Round to two decimal places as needed.) . greater than 10 when, in fact, the Data table .s than 10 when, in fact, the mean is :1 equal to 10 when, in fact, the mean is 11 10 12 8 Q 8 12 8 10 11 12 6 8 1O 10 9 12 13 8 6 -ual to 10 when, in fact, the mean is I when, in fact, the mean is less than t equal to 10 when, in fact, the mean 55 than 10 when, in fact, the mean is equal to 10. AType || error would be to conclude thatthe sample mean number of solderjoints inspected is 10 when, in fact, the mean is greater than 10. c. Conduct the hypothesis test you described in part a and interpret the tests results in the context of this exercise. Use a: 0.10. Calculate the value of the test statistic. z = (Round to two decimal places as needed.)
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