Cyber security question about authentication

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incorrect Question 14 0 12 pts Assume source elements of length 6 are mapped in some uniform fashion into target elements of length 3. Each digit can take on one of 9 possible values. Thus the number of source elements is 531,441 and the number of target elements is 729. A particular source element x is mapped to a target element y If the adversary is given element x, what is the probability the correct target element can be produced by the adversary in one try? (enter you answer as an exact decimal number like 0.X0XX0xx..XXxx) 0.0013717421 4) F7 FB FO F1o F1n F1L 9 Note that possible values of x are 531441 and possible values of y are 729 That is 531441 values are to be mapped in 729 values That is many different values will be mapped to the same value Since 531441 values are mapped in 729 values Therefore on an average, 5314441/729 729 values are mapped in 1 value In other words every 729 values are mapped to 1 value Here note that 729 represents X while 1 representsY It means that given any random value of Y, we need to try 729 different elements As either of them can be source element X And since every 729 elements are equally likely Hence Probability that the correct element is selected in one try is 1/729- 0.0013717421 I have tried to explain it in very simple language and I hope that i have answered your question satisfactorily.Leave doubts in comment section if any. incorrect Question 14 0 12 pts Assume source elements of length 6 are mapped in some uniform fashion into target elements of length 3. Each digit can take on one of 9 possible values. Thus the number of source elements is 531,441 and the number of target elements is 729. A particular source element x is mapped to a target element y If the adversary is given element x, what is the probability the correct target element can be produced by the adversary in one try? (enter you answer as an exact decimal number like 0.X0XX0xx..XXxx) 0.0013717421 4) F7 FB FO F1o F1n F1L 9 Note that possible values of x are 531441 and possible values of y are 729 That is 531441 values are to be mapped in 729 values That is many different values will be mapped to the same value Since 531441 values are mapped in 729 values Therefore on an average, 5314441/729 729 values are mapped in 1 value In other words every 729 values are mapped to 1 value Here note that 729 represents X while 1 representsY It means that given any random value of Y, we need to try 729 different elements As either of them can be source element X And since every 729 elements are equally likely Hence Probability that the correct element is selected in one try is 1/729- 0.0013717421 I have tried to explain it in very simple language and I hope that i have answered your question satisfactorily.Leave doubts in comment section if any