d. Determine the p-value. (Round to three decimal places as needed.) A. p-value = T.DIST.RT(1.84,12) = 0.045 B. p-value = T.DIST(1.84,10) = 0.096 C. p-value = T.DIST.RT(1.84,10) = 0.048 OD. p-value = 1-NORM.S.DIST(2.42,1) = 0.008 e. Choose the correct conclusion below. A. Do not reject Ho. There is sufficient evidence that >2. B. Reject Ho. There is sufficient evidence that >- C. Reject Ho. There is insufficient evidence that > 2. D. Do not reject Ho. There is insufficient evidence that >- Assume that you have a sample of n = 7, with the sample mean X = 41, and a sample standard deviation of S = 7, and you have an independent sample of n = 5 from another population with a sample mean of X2 = 33 and the sample standard deviation S = 8. Assuming the population variances are equal, at the 0.01 level of significance, is there evidence that H : a. Determine the hypotheses. Choose the correct answer below. A. Ho: H15H H: H1 H2 OC. Ho H H:12 B. Ho: H #H H:1-2 D. Ho: H H:15H2 b. Compute the pooled variance. (Round to three decimal places to the right of the decimal point as needed.) A. = O B. 0 . = = [(7 - 1) (7)] + ([5 1). (8)] (7-1)+(5-1) (7-1) (7)+(5-1). (8) (7-1)+(5-1) (7-1) (7)+(5-1). (8) (7-1)+(5-1) 2788 = = 278.8, using formula (10.1) 10 550 = 10 55, using formula (10.1) 74 = = 7.4, using formula (10.1) 10 D. (41+33) 74 p = = (7 +5) 6.167, using formula (10.5) 12 c. Then using the pooled variance, compute the test statistic. (Round to two decimal places to the right of the decimal point as needed.) A. (41-33) ZSTAT = 8 10.925 +2.42, using formula (10.5) [6.167 (1 6.167)] + 7 O B. (41 - 33) 8 = tSTAT +5.02, using formula (10.1) 1 1 2.537 7.4 5 0 . "STAT 278.8 (3341) 1 150 -8 =-0.82, using formula (10.1) 1 95.589 D. *STAT = (41-33) 1 1 55 + 5 8 = +1.84, using formula (10.1) 18.857 d. Determine the p-value. (Round to three decimal places as needed.) A. p-value = T.DIST.RT(1.84,12) = 0.045 B. p-value = T.DIST(1.84,10) = 0.096 C. p-value = T.DIST.RT(1.84,10) = 0.048 D. p-value = 1-NORM.S.DIST(2.42,1) = 0.008