Data:

Calculations:

Linear eqn

Final $T{T}_f$

$y=-0\mathrm{.}20104x+40\mathrm{.}73y=0\mathrm{.}21173x+41\mathrm{.}521$

$T$ change $Tq,14\mathrm{.}13$

$T$

$14\mathrm{.}728$

$q,Mg(s)q,$

$q,$

$q,$ MgO$(s)q,$

$q,4.$ Moles $Mg(s)q,$

$q,Mg(s)\mathrm{.}01282$

Calculate $q$ for each trial; show your calculation method in the space provided:

$Mg(s),$ Trial $1$

$q=(\mathrm{.}302g)(3\mathrm{.}97\frac{J}{g}z)(26\mathrm{.}6)=31\mathrm{.}902J$

$=31\mathrm{.}902(J{)}_{?}$

$Mg(s),$ Trial $2$

$q=(\mathrm{.}3115g)(3\mathrm{.}97\frac{J}{g})(26\mathrm{.}0g)=33\mathrm{.}14J$

$=33\mathrm{.}14J$

MgO $(s)$ Trial $1$

$q=(\mathrm{.}4132g)(3\mathrm{.}97\frac{J}{g}C)(26\mathrm{.}5C)=$

$=43\mathrm{.}47J$

MgO$(s)$ Trial $2$

$q=(\mathrm{.}4432g)(3\mathrm{.}47sgg)(26\mathrm{.}2C)=$

$46\mathrm{.}099J$

Calculate $H$ for each trial; show your calculation method in the space provided.

$\backslash$table$[[Mg(s),$ Trial $1,H_2=$