Data table Weight (carats) Price (dollars) 0.28 771 0.24 669 0.16 366 0.13 237 0.30 877 0.39 1,168 0.16 367 0.23 573 0.36 1,083 0.12 152 0.18 405 0.11 183 0.34 991 0.36 1,1 10 0.20 519 0.36 1,062 0.38 1,106 0.12 208 0.26 711 0.13 239Homework: HW CH19 Question 1, 19.1.37-T HW Score: 6.45%, 0.52 of 8 points Part 9 of 13 Points: 0.25 of 1 Save The data table found below contains the listed prices and weights of the diamonds in 20 rings offered for sale in a newspaper in a foreign city. The prices are in local dollars with the weights in carats. Complete parts (a) through (g) below. Click the icon to view the data table. (a) Scatterplot the listed prices of the rings on the weights of the rings. Does the trend in the average price seem linear? Which scatterplot below shows the listed prices of the rings on the weights of the rings? O A. B. O C. O D. 0.5 12007 1200T 0.5- Weight (carats) Weight (carats) Price (dollars) Price (dollars) 1200 0.5 0.5 1200 Price (dollars) Weight (carats) Weight (carats) Price (dollars) Does there seem to be a linear trend? A. No, because the scatterplot shows an obvious curved line. O B. No, because the scatterplot does not show any obvious pattern. C C. Yes, because the scatterplot shows an approximate linear pattern. O D. Yes, because the scatterplot does not show any obvious pattern. (b) Estimate the linear equation using least squares. Interpret the fitted intercept and slope. Be sure to include their units. Note if either estimate represents a large extrapolation and is consequently not reliable. Complete the equation for the fitted line below. Estimated Price (local dollars) = - 228.78 + 3611.75 Weight (carats) (Round to two decimal places as needed.)Which statement below best interprets the intercept? O A. The intercept is a unitless constant necessary to relate weight and price. O B. The intercept is the weight in carats of a ring with a price of 0 dollars. C. The intercept is the price in dollars of a ring with a diamond weighing 0 carats. D. The intercept is a large extrapolation and is consequently not reliable. Which statement below best interprets the slope? O A. The slope is a large extrapolation and is consequently not reliable. B. The slope is the average change in the price in dollars for each 1-carat increase in weight. O C. The slope is the average change in the weight in carats for each 1-dollar increase in price. O D. The slope is a unitless constant necessary to relate weight and price. (c) Interpret the summary values r and s. associated with the fitted equation. Attach units to these summary statistics as appropriate. 1 = 0.996 (no units) Se = 23.906 dollars (Round to three decimal places as needed.) What is the correct interpretation of r ? O A. The value of r is the fraction of the variation not accounted for by the least squares regression line. B. The value of r is the fraction of the variation accounted for by the least squares regression line. O C. The value of r is the average residual. O D. The value of r is the standard deviation of the residuals.What is the correct interpretation of Se? O A. The value of so is the average residual. B. The value of se is the standard deviation of the residuals. O C. The value of se is the fraction of the variation accounted for by the least squares regression line. O D. The value of se is the fraction of the variation not accounted for by the least squares regression line. (d) What is the estimated difference in price (on average) between diamond rings with diamonds that weigh 0.24 and 0.33 carat? The difference is |dollars. (Round to the nearest dollar as needed.)