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data to answer question is attached (b3 and b4) 2c) Consider Experiment B in which the variable VH,0 changed values between test tubes having the
data to answer question is attached (b3 and b4)
2c) Consider Experiment B in which the variable VH,0 changed values between test tubes having the same VNaou (e.g, between test tubes B3 and B4). Was the relationship between the two variables Nnaoh and AT affected by the variable VH0? Support your reasoning using data from the group file as evidence. [Hint: you may want to calculate average values of the dependent variable for each value of VH,0] B D E F G Sample Number me of H20 (-0.1me of NaOH (+/-0.fume of HCI (+-0.0ial Temp (+1-0.5 al Temp (+/-0.5 Ita T (+/-0.5 Observations B1 Observations (graph) 14 0.6 15.0 21.0 Sample B1 A 1.4 24.0 3.0 change in temperatur Graph has undefined sk B4 0.6 4 B 10.0 21.0 22.0 1.4 1.0 The temperature only My graph shows that there was very lit 0.6 5 B1 15.0 14 21.0 25.0 4.0 the temperature incre The graph had a positive correlation to 0,6 15.0 6 B1 23.0 27.0 14 4.0 Temperature increase the graph showed that the time 2 min 0.6 2 1 15.0 22.0 25.0 1.4 3.0 The temperature incre The graph was a scatter plottt and then 0.6 10.0 8 B1 14 21.0 23.0 2.0 Temperature increase the graph was all over the place and th 0.6 150 9 B1 23.0 27.0 1.4 4.0 The temperature incre There was no obvious correlations betw 0.6 10 B2 10.0 21.0 22.0 1.4 1.0 The temperature incrtthere were a lot of outliers. Therefore, 11 B1 0.6 15.0 23.0 1.4 27.0 4,0 The temperature grad When graphing the temperature as a fu 0.6 12 51 15.0 21.0 1.4 22.0 1.0 When the HCL was added the temp was 25 and was the highes 113 B1 0.6 15.0 14 21.0 23.0 0.6 2.0 The temperature increased by 2 degrees Celsius after adding 15.0 14 81 21.0 23.0 1.4 20 The temperature increased by 2 degrees after HCl was added 0.6 15 Bi 25.0 1.4 20.0 22.0 2.0 increased slightley 16 B1 0.6 15.0 210 24.0 1.4 3.0 Temperature increse of 3.0 degrees 0.6 17 82 15.0 21.0 1.4 24.0 0.6 3.0 The temperature increased by 3 degrees after adding the HCL 18 82 15.0 22.0 26.0 4.0 The temputerature signficantly increased after the addition of 0.6 15.0 19 B2 23.0 25.5 1.4 2.5 temp increased by 2.5 different solutions chan B1 0.6 20 82 15.0 4.4 20.0 24.0 4.0 Temp increased by 4.Graph showed a constant relationship be 0.6 21 82 15.0 18.0 19.5 15 Temperature increase Slight linear relationship 0.6 22 82 15.0 218 23.0 44 1.2 The temperature incre The graph had a positive outlook and the 0.6 15.0 23 32 21.0 25.0 4.4 4.0 The temperature incre The graph is a straight line at the 2 minut 0.6 15.0 22.0 27.0 5.0 The temperature of the graph is in the form of a scatter plot but 125 82 0.6 15.0 23.1 25.0 44 0.6 19 The temperature in the graph was a vertical constant 15.0 2682 22.0 25.0 4.4 3.0 temperature increase the graph was also a scatterplot dit was 0.6 15.0 22 32 22.0 240 20 There was a small terr The temperature chance did not very amo 0.6 10.0 28 2 17.0 18.0 44 10 The temperature incre There are 4 outliers 0.6 15.0 21.5 23.0 4,4 0.6 15 The temperature rose There is a constant relationship because 30 B2 15.0 20.0 25.0 5.0 The temperature in There was a positive linear trend between 0.6 31 32 15.0 21.0 22.5 4,4 15 Temperature increase There was no constant relationship 0.6 15.0 32 B2 210 23,5 2.5 The temperature incre There was no constant relationship 0.6 15.0 21.0 225 33 82 4.4 15 The temperature incre This was an outler on the bottom of the gr 15.0 21.0 34 82 220 10 The Tempurature increased by 1 degree Cafter the HCl was adde 0.6 35 B2 10.0 17.0 18.0 4.4 10 During the 2 minute time frame, the temperature slowly increase 0.6 15.0 36 B2 210 22.3 0.6 1.3 Temp increased by 1.3 degrees Celsius 15.0 37 B2 22.1 23.9 4.4 1.8 temp increaed by 18 15.0 22.0 38 32 24.0 2.0 The temp increased by 2 degrees 0.6 15.0 220 24.0 39 B2 44 0.6 2.0 temp increased by 2 degrees 15.0 23.0 40 B2 25.0 2.0 The temperature increased by 2 degrees Celsius 4.4 0.6 15.0 41 B2 22.0 24.0 4.4 2.0 The temperature increased by 2 degrees 0.6 inn 2482 44 29 B2 44 0.6 0.6 4.4 D E 1.0 1.0 oo 1.0 1.0 1.0 1.0 OOOOO 1.0 1.0 1.2 1.0 1.2 0.8 1.0 0.8 1.0 1.0 1.0 1.0 1.0 OOO 1.0 45 B3 46 B3 47 B3 48 B3 49 83 50 B3 51 B3 52 B3 53 B3 54 B3 55 B3 56 B3 57 B3 58 B3 59 B3 60 B3 61 B3 62 B3 63 B3 64 83 65 B3 66 B3 67 B3 68 B3 69 B4 70 B4 71 B4 72 B4 73 B4 74 B4 75 B4 76 B4 77 B4 78 B4 79 B4 80 B4 81 B4 82 B4 83 34 84 B4 85 B4 86 B4 1.0 1.2 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 4.0 4.0 4.0 4,0 4.0 4.0 15.0 15.0 15.0 15.0 15.0 15.0 10.0 15.0 15.0 15.0 15.0 15.0 10.0 10.0 15.0 15.0 15.0 15.0 15.0 15.0 15.0 15.0 15.0 1.0 1.0 1.0 0.8 1.0 1.0 1.0 1.0 1.0 1.0 1.0 0.6 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 E 21.5 21.0 21.5 24.0 21.5 22.0 21.0 22.0 22.5 23.0 21.0 24.0 21.0 21.0 22.0 21.0 21.0 20.5 21.0 21.0 20.5 22.1 21.5 F 26.0 29.0 26.1 33.0 30.0 27.0 22.0 27.0 28.5 29.0 25.0 30.0 22.0 22.0 20.0 23.5 24.0 24.0 24,5 25.0 25.0 30.0 30.0 G H 4.5 change in temperat 8.0 The temperature in 4.6 The temperature slo 9.0 Temperature increas 8.5 The temperature inc 5.0 The temperature in 1.0 Temp increased by 1 5.0 The teperature chane 6.0 The temperature incr 6.0 The temperature incr 4.0 The temperature incr 6.0 With the higher volum 1.0 Temperature increase 1.0 The solution was origi 2.0 The temperature decre 2.5 The temperature incre 3.0 The temperature incre 3.5 Increase temperature 3.5 One drop of phenolpht 4.0 The temperature increa 4.5 Temperature increse of 7.9 15 mL was quite a lot to 8.5 The temperature raised This solution had the hi 6.5 temp incresed di 4.5 Temp increased by 4.5G 2.0 Temperature increase SI 2.8 The temperature incre The 4.0 The temperature increth 4.0 The temperature of th Th 5.2 The temperature increth 1.0 Temperature increase The 6.0 The temperature incre The 4.0 The temperature increThe 2.5 Temperature increase The 9.0 The temperature incre The 1.0 Increase in temperautre b 2.0 The temperature increase 2.0 It took more than 2 minute 2.5 The temperature increase 2.5 The temperature gradually 29.5 24.5 20.0 23.8 25.0 27.0 28.0 23.0 4.0 15.0 15.0 15.0 15.0 15.0 15.0 15.0 15.0 15.0 15.0 15.0 15,0 10.0 10.0 10.0 15.0 10.0 15.0 4.0 4.0 4.0 4.0 4.0 4.0 4.0 4,0 4.0 4.0 4,0 23.0 20.0 18.0 21.0 21.0 23.0 22.8 22.0 21.0 20.0 21.0 21.0 19.0 21.0 17.0 22.5 20.5 20.0 27.0 1.0 OOOOOOO 24.0 23.5 30.0 20.0 23.0 19.0 25.0 23.0 Dan 1.0 1.0 1.0 4.0 4.0 4.0 4.0 4.0 4.0 4.0 4.0 4.0 4.0 4.0 B4 1 B4 2 B4 13 B4 4 B4 15 B4 76 B4 7 B4 18 B4 79 B4 80 B4 81 B4 82 B4 83 B4 84 B4 85 B4 86 B4 87 B4 88 B4 89 B4 90 B4 91 B4 92 B4 93 B4 94 B4 95 B4 96 B4 4.0 4.0 4.0 4.0 4.0 4.0 4.0 4.0 4.0 4.0 4.0 4.0 4.0 4.0 4.0 4.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1,0 1.0 1.0 15.0 15.0 15.0 15.0 15.0 15.0 15.0 15.0 15.0 15.0 15.0 10.0 10.0 10.0 15.0 10.0 15.0 15.0 15.0 15.0 15.0 15.0 15.0 15.0 15.0 15.0 20.0 18.0 21.0 21.0 23.0 22.8 22.0 21.0 20.0 21.0 21.0 19.0 21.0 17.0 22.5 20.5 20.0 20.0 20.8 22.0 22.0 22.0 21.0 21.5 22.1 20.5 24.5 20.0 23.8 25.0 27.0 28.0 23.0 27.0 24.0 23,5 30.0 20.0 23.0 19.0 25.0 23.0 23.0 24.0 25.0 27.0 27.0 28.0 27.0 27.5 28.2 29.5 4.5 T 2.0 T 2.8 T 4.0 T 4.0 T 5.2 T 1.0 TS 6.0 TH 4.0 TH 2.5 Te 9.0 Th 1.0 Inc 2.0 Th 2.0 Itt 2.5 Th: 2.5 The 3.0 The 4.0 the 4.2 Ten 5.0 ten 5.0 The 6.0 the 6.0 Tem 6.0 The 6.1 tem 9.0 Only OOOOO Step by Step Solution
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