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DBMS Assume one file has records. Each record takes R = 100 bytes, of which 10 bytes are for the key of the record. Suppose

DBMS

Assume one file has image text in transcribed records. Each record takes R = 100 bytes, of which 10 bytes are for the key of the record. Suppose the key values range from 1 through 1,000,000, inclusive. Assume the block size B is 1000 bytes for all files, and that an address (block pointer, tree node pointer, or data record pointer) takes 10 bytes.

What is the number of B-+tree internal nodes at the next highert level needed if blocks are approximately 69% full (round up for convenience)?

(Please note this internal level is just above the B-+tree lowest internal node level).

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