Answered step by step
Verified Expert Solution
Question
1 Approved Answer
def count_upper(a_string): count = 0 if len(a_string) < 1: return 0 else: if a_string[0] == a_string.upper()[0]: count += 1 count_upper(a_string[1:]) return count else: count_upper(a_string[1:]) return
def count_upper(a_string): count = 0 if len(a_string) < 1: return 0 else: if a_string[0] == a_string.upper()[0]: count += 1 count_upper(a_string[1:]) return count else: count_upper(a_string[1:]) return count
Step by Step Solution
There are 3 Steps involved in it
Step: 1
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started