def crop(map, r1, c1, r2, c2): Given a map and two locations, create and return the map that only contains rows from r1 to r2 (inclusive), and columns from c1 to c2 (inclusive). If r1>r2 or c1>c2, the answer has no rows/columns (we return []). Similar to how slicing works, if more rows or columns are requested than exist, just return the parts that do exist. Remember, you must not modify the original map. Assume: map is a map as defined above, and r1, r2, c1, and c2 are int values. crop(map1,1,1,3,3) [[1,1,1],[1,3,1],[1,3,1]] crop(map5,3,1,3,4) [[3,5,12,4]] crop(map2,1,1,90,90) [[0,0,10,0,0,1],[0,1,3,1,1,1]] crop(m1,2,2,1,3) []