Define a pure function delta that takes a function f as an argument and computes the forward difference of f$.$ The mathematical definition of the forward difference operator, written

$\backslash$Delta

$,$ is

$\backslash$Delta

f

$($

x

$)$

$=$

f

$($

x

$+$

$1$

$)$

$$

f

$($

x

$)$

Note that the argument f is a function, as is the value returned by delta. That is$,$ delta is a higher$-$order function. You will want to use a lambda expression in your solution.

The following fact may help you test your implementation:

For all numbers n$,(($delta $($lambda $($x$)$ x$))$ n$)$ should be equal to $1($why$?).$