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Design a combinational circuit that takes four inputs ( E ( the enable ) , A , B , and C ) , has four

Design a combinational circuit that takes four inputs (
E
(the
enable
),A,B, and C ), has four outputs (X,Y,Z, and S (the end of sequence flag)) and meets the following specifications. If ABC=111 then, regardless of the value of E, the end of sequence flag S=1 else S=0. If E=1 then XYZ=ABC. If E=0 and ABC
=111 then XYZ should be set to the code after ABC in this list: 000,100,101,001,011,010,110,111. So if ABC=010 then XYZ=110. This is a type of Gray code sequence. If E=0 and ABC=111, then XYZ may be set to anything (this is called a "don't care" and should be represented in the truth tables and K-maps with an\times . Notice that this is essentially a description of a four input, four output truth table a.Pre-Lab> Create a truth table (with the operands in this order E,A,B,C,X,Y,Z,S ) for this combinational circuit's function. The first three lines of the truth table look like this: b.Pre-Lab> Write Boolean expressions for each output. Write the expressions as sum of minterms. c. PPre-Lab> Simplify each expression using a K-map (4 variable K-maps will be used).(Show the maps, minterm groupings, and final expressions. Remember there is a convenient K-map template that is available if desired in the moodle resources section.) d. Pre-Lab> Create the logic circuit.

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