Determine the enthalpy change for the reaction of $1$ mole of $H_2(g)$ with $1$ mole of $C{l}_2(g)$ if both the reactants and products are at standard state conditions.

The standard enthalpy of formation of $HCl(g)$ is $-92k\frac{J}{m}ol.$

$-46kJ$

$-184kJ$

$124kJ$

$65\mathrm{.}3kJ$