Determine the equilibrium constant K_eq of TA in this sample of tea.

the initial concentration of [TA] in a 150. mL of tea: 1.75 x 10^-3 M

the concentration of TA at equilibrium: 9.00 x 10^-3 M

the mass of TA: 0.2387g

the concentration of [H⁺]: 9.55 x 10^-6 M

Equation: TA (aq) + H+ (aq) <-> TAH+ (aq)

Group of answer choices

1.0 x 10^-5 M^-1

9.9 x 10⁵ M^-1

9.9 x 10⁵

1.0 x 10^-5