Determine the lattice enthalpy of KCl by using the following enthalpies: Atomisation: K(s) K(g) = 89 kJ/mol Bond dissociation: Cl2(g) + 2 Cl(g) = 242 kJ/mol lonisation: K(g) K*(g) + e* = 419 kJ/mol Electron gain: Cl(g) + e + Cl (g) = -349 kJ/mol Formation: K(s) + Cl2(g) KCl(s) = -436 kJ/mol