Determine the precise (i.e., not just the order of magnitude) Big-Oh values for the following code sample, based on the number of statement executions, as described in the Module 1 lecture. For example:

for(int i = 0; i < n; i++){

 sum += i;

}

int j = 0;

while(j < n){

 sum--;

 j++;} Answer = O(6N+4) 

1)

for(int i = 0; i < n; i++){

for(int j = 0; j < n; j++){

sum += i;

sum -= (j + 1);

}

}

2)

for(int i = 0; i < n; i++){

for(int j = 0; j < n; j++){

sum += i;

sum -= (j + 1);

}

}