Devise formulas to calculate my_first_i and my_last_i in the following code snippet from the lecture. Assume that p (number of cores) and n (number of values) are available to all cores, and each core has a value my_id, which is a unique identifier between 0 and n-1. You can also assume n is divisible by p = = my_sum 0; my_first i my last i = for (my_i=my_first_i; my_i